kindly find the attachment. I want to find out the radius of an imported curve in part model.
The curve pts were taken by "FARO"
Thanks in Advance.
Your model returns me an error. Cannot be read. May be a SLD versions issue.
Lets go step by step and may be it will help you.
The following example is related to a 2D curve. For a 3D one, the plane definition only would be different.(Through three points)
Select the curve and create a plane(Will be co-planar with the curve)
Select the new plane and create a sketch on it. Project/transfer the curve on/to the sketch.
3-) Draw a random line at the concave side of the selected curve section (The one which radius is going to be found), and constrain it to be tangent to the curve at anypoint(inside the section under study).
Points P and Q are only marked as a visual reference for the curve segment under study.
4-) Drag one point of the line. At the inflexion point of the curve(Where it changes from convex to concave), you will observe that the point cant be dragged anymore.
This will be the REAL point Q.
5-) I've marked this poit (the tangency point) as D.
Now draw two chords, segments between both ends of the curve section.(C1 and C2 at the pic) and their corresponding perpendicular bisector lines.
6-) Distance O-R is the radius of the curve section, limited from D to the upper end point.
I cannot open the attached file. Hence Im only trying to guess what you are asking for.
If you want to get the radius we are dealing with a circle arc. As its known from basic geometry; If an inscribed triagle is drawn in the circle, the perpendicular bisectors to the sides, will cut at a point, that is the center of the circle.
It's obvious that only two sides are required, as only two bisectors are required to get a cutting point.
Draw two segments with a common vertex, where all three vertex are touching the curve section (Two sides of the inscribed triangle)
Draw both perpendicular bisector lines. Their cutting point, will be the center of the arc.
Now, measuring the radius is trivial.
Here is the part file could you kindly view it and can provide me the solution
Thanks in Advance!!!
Center results from the cutting point of both bisectors.
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