Looking at the sphere: the Reynolds number for a sphere of 0.2m diameter in a uniform water flow of 1.54 m/s is on the order of 10^5, well within the turbulent region. You can ignore laminar flow here, the turbulence model will take care of the boundary layer. Let's do a simple analysis using the drag equation:
Fd = .5 * (density) * (speed)^2 * (drag coefficient) * (projected area)
Fd = .5 * (1035 kg/m^3) * (1.54 m/s)^2 * .47 * (pi * [0.1m]^2) = 18.1 N
The mass required to produce 18.1 N under Earth gravity = 18.1 N / 9.81 m/s^2 = 1.85 kg, pretty darn close to what Flow Simulation spat back at you.
p.s. why are you using this strange "kg-f" unit? I never heard of that before reading your post. Sounds like something they use in the imperial unit system to deal with the confusion between pound-force and pound-mass.
Kgf is a pretty standard engineering unit. It's as bad as the lbf lbm, and gets used for the same reasons.
Thanks for breaking that down Amit. It was a great help
this comes up a lot
have you already looked at the tutorials and validation examples about aerodynamic drag? flow over a sphere is one of the examples and i think you'll find the answers to all your questions there
generally when running these simulations the issue is either the method of output (global goal is good but surface goal is also a good double check in case you ever want to add any other geometry)
next folks generally don't have a big enough computational domain or sufficient mesh, adaptive meshing and control planes really help
and finally sometimes transient is required
check out the documentation and let us know if you still have questions
I'll have a look at the documentation Jared. Thanks again.