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Torsional response of a node in solidworks simulation

Question asked by Gopal Koya on Nov 3, 2014
Latest reply on Feb 3, 2015 by Jared Conway

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Hello,

I am running a harmonic analysis on drill bit. I gave an axial force and I wanted to know how much torsional deformation does it produce on the drill bit. As of what I know, solidworks gives the nodal displacements only (X, Y, Z displacement of the nodes). But I wanted to know the torsional deformation of the whole drill bit. Is there any possible way to get it? Basically I need the torsional deformation response from solidworks (instead of Ux, Uy Uz URES etc.). Please help me. I've been struggling.

Gopal Koya Nov 6, 2014 10:57 PM

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That is something on which I ran the harmonic study. And I marked the node for which I want the torsional response. The simulation gives me the response for Ux and Uy. But I need to know the response for the angular displacement. Or atleast I should know the angular displacement of that particular node for all plot steps.

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Jared Conway Nov 4, 2014 10:41 AM

choose an axis

that gets you cylindrical coordinate outputs

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Gopal Koya @ Jared Conway on Nov 6, 2014 7:34 PM

I am doing a harmonic analysis. I am looking for the response graph for tangential displacement. But I don't see an option for selecting the axis if I am in the response graph tab. Basically, I am looking for the torsional response and not the displacement. Can you please help me on this?

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Gopal Koya Nov 6, 2014 10:57 PM

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Shivani Patel @ Gopal Koya on Nov 7, 2014 5:17 PM

Seckin's link should tell you exactly how to do what you're looking for. You want angular displacement over time, so you need to put your UY displacement plot into tangential displacement, export the time based results, and then do a manual conversion yourself in EXCEL. Sorry, but there is no way to do this using the response graphs.

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Jared Conway @ Gopal Koya on Nov 8, 2014 11:11 AM

Plot the right parameter.

probe your location

create response graph

im not in front of swx but you might be right that you can't choose an axis

did you at least find what I mean on normal plots?

worst case, output xyz and manually convert to cylindrical

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Gopal Koya @ Jared Conway on Nov 8, 2014 6:16 PM

Yes I know what you mean on normal plots. I have 190 plot steps for the harmonic analysis I did. I think it would be really difficult to get the coordinates for each and every plot step. Is that what you mean or did I miss anything?

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Jared Conway @ Gopal Koya on Nov 10, 2014 12:08 PM

You plot based on location. The plot will show all 190 steps per location.

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Gopal Koya Feb 1, 2015 6:47 PM

I didn't find the actual solution. But in my case, the torsional response to an axial harmonic excitation is same as the axial response to a torsional harmonic excitation. I failed to find out the former and got adjusted with the latter result. But they both are not the same in all the cases.

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Jared Conway @ Gopal Koya on Feb 1, 2015 10:40 PM

what did not work with the solution provided above?

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Gopal Koya Feb 2, 2015 10:12 AM

I tried to change the coordinates to cylindrical. But, the problem is that the drill bit I shown above in the figure has a displacement laterally also (I mean on the plane of cross section) which prevents me from using direct coordinate transformation.

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Jared Conway @ Gopal Koya on Feb 3, 2015 2:25 PM

why not output 2 separate sets of results?

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12 Replies

Seckin Uslu Nov 4, 2014 3:23 AM
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Maybe this link SolidWorks Simulation: How to Get the Angle of Displacement wil be helpful
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Jared Conway Nov 4, 2014 10:41 AM
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choose an axis
that gets you cylindrical coordinate outputs
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- Gopal Koya @ Jared Conway on Nov 6, 2014 7:34 PM
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  Correct Answer
  I am doing a harmonic analysis. I am looking for the response graph for tangential displacement. But I don't see an option for selecting the axis if I am in the response graph tab. Basically, I am looking for the torsional response and not the displacement. Can you please help me on this?
  Like • Show 0 Likes0
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Gopal Koya Nov 6, 2014 10:57 PM
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Correct Answer
That is something on which I ran the harmonic study. And I marked the node for which I want the torsional response. The simulation gives me the response for Ux and Uy. But I need to know the response for the angular displacement. Or atleast I should know the angular displacement of that particular node for all plot steps.
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- Shivani Patel @ Gopal Koya on Nov 7, 2014 5:17 PM
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  Seckin's link should tell you exactly how to do what you're looking for. You want angular displacement over time, so you need to put your UY displacement plot into tangential displacement, export the time based results, and then do a manual conversion yourself in EXCEL. Sorry, but there is no way to do this using the response graphs.
  Like • Show 1 Like1
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- Jared Conway @ Gopal Koya on Nov 8, 2014 11:11 AM
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  Correct Answer
  Plot the right parameter.
  probe your location
  create response graph
  
  im not in front of swx but you might be right that you can't choose an axis
  
  did you at least find what I mean on normal plots?
  
  worst case, output xyz and manually convert to cylindrical
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  - Gopal Koya @ Jared Conway on Nov 8, 2014 6:16 PM
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    Yes I know what you mean on normal plots. I have 190 plot steps for the harmonic analysis I did. I think it would be really difficult to get the coordinates for each and every plot step. Is that what you mean or did I miss anything?
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    - Jared Conway @ Gopal Koya on Nov 10, 2014 12:08 PM
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      You plot based on location. The plot will show all 190 steps per location.
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Gopal Koya Feb 1, 2015 6:47 PM
Mark Correct
Correct Answer
I didn't find the actual solution. But in my case, the torsional response to an axial harmonic excitation is same as the axial response to a torsional harmonic excitation. I failed to find out the former and got adjusted with the latter result. But they both are not the same in all the cases.
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- Jared Conway @ Gopal Koya on Feb 1, 2015 10:40 PM
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  what did not work with the solution provided above?
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Gopal Koya Feb 2, 2015 10:12 AM
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I tried to change the coordinates to cylindrical. But, the problem is that the drill bit I shown above in the figure has a displacement laterally also (I mean on the plane of cross section) which prevents me from using direct coordinate transformation.
Like • Show 0 Likes0
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- Jared Conway @ Gopal Koya on Feb 3, 2015 2:25 PM
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  why not output 2 separate sets of results?
  Like • Show 0 Likes0
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Torsional response of a node in solidworks simulation

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