Hi guys, got two questions for you today
1. How do I apply pressure on the inside edge of a round cylinder, in an angle of 45 degrees? As I see not it only lets me to choose a surface, and no control over angle
2. Whats the difference between choosing a pressure or force on solidworks? seems the same when I do the simulation.
Thanks!
Hi, thanks for the reply!
1. a. There's no other way to draw a sketch line with a 45 degree angle and "tell" the force to go in that direction?
b. I can't seem to find a way to let the force be on the edge and not the entire surface
a. not in cylindrical coordinate systems. if you had cartesian it is straightforward like that.
b. maybe try the selection with your selection filter for edges selected.
Stress = F/A
an edge has no area so your stress on that edge would approach infinite.
Perhaps what you need to do is Split a face area near the end.
Can you attach your sldprt file here?
It occured to me that maybe a chamfer will solve your problem.
Hi,
Part attached.
The wrap is there because thats where I have a fixture.
This is basically a rubber sleeve attached with a glue (wrap feature) to something that looks like the bottom of a baloon (see attached picture).
I might be analyzing it all wrong but I figured a good estimate of the deformation of the sleeve outwards which depends on the inflation of the baloon, can be achieved by applying a force around the top edge where it starts to expand.
Hope i'm getting myself through..
Thanks for the help much appreciated, would love tips if you think i should take another approach
this method should be fine
Does it matter how small the chamfer surface area is?
For example, if I know the pressure inside the baloon is 6000 pascal I apply that pressure in solidworks on the chamfer regardless of its area?
the chamfer is a workaround for you not wanting to calculate the components of force. so choose whatever you feel is appropriate. remember that the equation for fea is F = kx, so essentially the pressure is just being back calculated into a force in the end .
chamfer. NICE idea!
1. determine the components of force in the axial (along the axis) and radial direction and apply them separately
2. force vs pressure, really not much of a difference other than unit of input. one is force over the area on is just the total force. in nonlinear there are some options about the direction updating but don't worry about that too much for this question.