"3- If I put Temperature of 148c in parameter of heat sources the component will stay all the time at 148c with or without enclosure"
the output of simulation is basically temperature. so when you force the boundary condition, it will stay at that temperature.
sounds like to me you don't know what the power is.
so what you could do is use the parametric study to run an analysis where you setup the environmental conditions and ask the software to find what power produces 148deg C. once you have that, you can put it in a box with that power and it will tell you what temperature it gets with the box.
if you know the power, then you can just input it into your open air simulation, verify the results are 148 and if not, adjust parameters (environment..material...etc). and then move to your box analysis.
thank you Thank you
I know power but I am new with this Software
But thank you thousand time you just made my day and save my ..........
could you show me one small example with any temperature or any simple geometric shape .
if not thank you again.
god be with you
hi habib, i'd start with the tutorials. the one with the circuit board would be a good first start.
Thank you Mr. Jared Conway
Hi Dear sir
One more question
when I create my parts (lets say simple square) and I apply 5W volume heat generating source
and run external analyses should I choose gravity with heat conduction in solid or I should apply initial velocity in normal room temperture
and what is my velocity in normal room condition.
then put it in my box.
seems like a reasonable simulation but i think you need to spend some time on simplification of your model.
habib, i don't understand your question.
if you want to include convection, enable gravity.
if you have a forced convection case, then velocity is probably enough because it will overpower your natural convection from gravity. if the air is still, set it at 0 and let gravity do its work.
remember that for internal analysis, these are initial conditions.
for external they are ambient conditions.
but regardless, the solution will converge to the result if they are different.