i have an arm i have drawn and was wondering can i balance this in an assembly i need it to be upright under its own weight and need to add weights to the bottom
to do this is it possable would save a lot of trial and error
Not real sure what you mean by it needing to be "upright" but this is my guess. If you run mass properties then you will see the center of mass. For this to stand upright on the flat bottom, that center of mass must be inside the bounds of the face that the part is sitting on. If you intend to hang it by one of the holes, then it will hang such that the COM is directly below the hang point.
i didnt explain to well this is finished art work the two arms go backwards and foward (thought ide show you picture makes it a clearer ) what i wanted to do in an assembly is to first off place a 8mm shaft for the arm to swing on and the real amm lays horizontial at momant i need to balance both them so they sit upright when not connected to the big wheels the arms reverse the two wheels at the end of there stroke so i need to place lead weights and also might have to change the shape of the arm
and wanted to do it in solidworks so it can sit on the centre pin 8mm if that makes any scence
thanks for your help
I sort of maybe get the idea....
But the same thing applies - in the assy, highlight the part you want to hang a particular way, and the hit your Mass properties. In real life, the part will rotate such that the COM indicator is directly below the pivot point.
So if what you want is for the arm part that you sent and is seen on the LH side to hang about like you see it in your pic, you will have to add mass to the "back" RH side - all of your mass is to the left of the pivot at this point.
But then again, I now see strings attached to the tops of those arms, therefore they don't just hang. I may be all confused as to what you want - sorry.
Ok, so maybe you just need the COM to be to the left of the pivot in order for the string to always have tension and to not have the part fall over to the right?? :-) If that's the case, then the COM needs to be far enough to the left of the pivot such that when you pull the arm, it doesn't have enough inertia to take it over center. That would be dependent on the speed vs. the friction in the joint.
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