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What the numbers mean

Question asked by George Edwards on Feb 14, 2011
Latest reply on Feb 15, 2011 by Anthony Botting

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I tried to search for this but probably didn't use the correct wording.

Can you tell me what the numbers mean under the displacement when using analysis?

There is a little box that gives the model name, study name, plot and a value for the deformation scale of 0.412422.

The color scale on the side has a min value and max value and is labled URES (mm). (what's URES?)

The Values in the color scale range from 1.000e-030 - 1.648e+002 Is that 1.000000, and .001648?

How are these numbers interpreted, and what is the purpose of the deformation scale number?

Thanks for the help.

Anthony Botting Feb 14, 2011 5:33 PM

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The letter "U" is the vector representing displacement. U is commonly used in the analyst community when talking about displacements. The vector U has components Ux, Uy and Uz. These are the values solved by the finite element analysis in each orthogonal direction, which you can plot separately (Edit definition and you will see options for UX and UY and UZ). If you want the "magnitude", or "resultant" or "length" of the vector, as you probably recall, you can square the components of the vector, add them, and take the square root and obtain a non-signed answer (it's just a magnitude). The scale shows annotation "URES" to mean the U values are the RESultant of the displacement. Hope that helps a little. - Tony

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Chris Michalski Feb 14, 2011 4:59 PM

the deformation scale is the ratio of deformation shown vs. reality - i.e. your .412422 means that if the part actually bends 1" it would display it only bending .41". It's basically an exaggeration factor - making it higher makes your model look like jello, but for very stiff models you need a higher deformation scale than for very flimsy parts.

URES (I don't recall the acronym, but it's the displacement from the intial location of each element)

The 1e-30 means .000(thirty zeros...)1 and yes, 1.6482e+2 = .0016482 - SW uses small e for scientific notation instead of 10^

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George Edwards @ Chris Michalski on Feb 14, 2011 5:18 PM

So, 0.1 would be 0.041 according to the deformation scale.

Could URES be Units Resolution?

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Anthony Botting Feb 14, 2011 5:33 PM

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George Edwards @ Anthony Botting on Feb 14, 2011 6:01 PM

Like I,J,K values for vectors.

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Anthony Botting @ George Edwards on Feb 15, 2011 9:55 AM

Yes you're right. So, formally it would be written as a vector: U = Ux(I) + Uy(J) + Uz(K). Then URES = SQRT ([Ux]^2 + [Uy]^2 + [Uz]^2) is the magnitude of the vector.

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Chris Michalski Feb 14, 2011 4:59 PM
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the deformation scale is the ratio of deformation shown vs. reality - i.e. your .412422 means that if the part actually bends 1" it would display it only bending .41". It's basically an exaggeration factor - making it higher makes your model look like jello, but for very stiff models you need a higher deformation scale than for very flimsy parts.

URES (I don't recall the acronym, but it's the displacement from the intial location of each element)

The 1e-30 means .000(thirty zeros...)1 and yes, 1.6482e+2 = .0016482 - SW uses small e for scientific notation instead of 10^
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- George Edwards @ Chris Michalski on Feb 14, 2011 5:18 PM
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  So, 0.1 would be 0.041 according to the deformation scale.
  
  Could URES be Units Resolution?
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Anthony Botting Feb 14, 2011 5:33 PM
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The letter "U" is the vector representing displacement. U is commonly used in the analyst community when talking about displacements. The vector U has components Ux, Uy and Uz. These are the values solved by the finite element analysis in each orthogonal direction, which you can plot separately (Edit definition and you will see options for UX and UY and UZ). If you want the "magnitude", or "resultant" or "length" of the vector, as you probably recall, you can square the components of the vector, add them, and take the square root and obtain a non-signed answer (it's just a magnitude). The scale shows annotation "URES" to mean the U values are the RESultant of the displacement. Hope that helps a little. - Tony
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- George Edwards @ Anthony Botting on Feb 14, 2011 6:01 PM
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  Like I,J,K values for vectors.
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  - Anthony Botting @ George Edwards on Feb 15, 2011 9:55 AM
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    Yes you're right. So, formally it would be written as a vector: U = Ux(I) + Uy(J) + Uz(K). Then URES = SQRT ([Ux]^2 + [Uy]^2 + [Uz]^2) is the magnitude of the vector.
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