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Insertion Force Analysis

Question asked by Aaron Bobuk on Nov 19, 2010
Latest reply on Nov 19, 2010 by Aaron Bobuk

I'm wondering how to solve the following problem using Solidworks Simulation: I want to be able to determine the force that it would take to insert a pin in a slot (accounting for normal and frictional force).

 

Here's an example screenshot of what I'm looking to do:

PinInSlotConfiguration.jpg

  • I'm holding the base of my slot fixed (shown in green)
  • have rollers/sliders to constrain y & z movement of my pin (shown in red)
  • I'm applying a 2mm displacement on the pin to shove it into the slot (shown in magenta)
  • I have a contact set defined between the pin/slot as "no penetration" with the coefficient of friction defined between the 2 faces as .5

 

After I run the static FEA analysis (don't have dynamic package) I end up with a force on the back face of the pin of 0.0044 lbs.  But, if I just perform a displacement on the slot (deform it as it will when the pin is inserted), I get a resultant force 0.015 lbs.  So I'm going wrong somewhere: my insertion force due to friction will be higher (0.5*0.015 lbs) than the 0.0044 lbs specified from the simulation of the pin going into the slot.

 

Any help would be greatly appreciated.

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