I was thinking about this earlier today. I know that the yield strength of copper is about 18.76 tons/sq.in. The surface area of the smashed part should be about 10 sq.in. So, can I put the two together and say: 10 x 18.76 = 187.6 tons of pressure required to smash the stud? Any thoughts on this would be greatly appreciated.
if you want to try to use solidwork for this you need to go all the way up to Simulation premium (or professional - I forget) you need nonlinear analysis.
there are hand calculations that would probably get you close enough, though I haven't used them in years so I am not going to try to post them here from memory. I can tell you that you example calculation is giving you a low number since it does not take into account "strain hardening". a lot of metals (copper especially) get harder the more you deform them. ever try to straighten a copper wire?