I'm trying to model a red blood cell shape using the equation:
Can anyone give me any info on how I may approach this?
While I don't know the best answer for this, I did look it up on wolfram alpha:
+z - WolframAlpha
-z - WolframAlpha
and if you wanted to see a lot of numbers using this equation:
lots of numbers - WolframAlpha
Using your linked equations, this seems to work well. It's not scaled properly so I haven't verified if the volume vs surface area makes sense. Good luck!
Thank you for all the help! Would it be possible to attach the RBC part that can work on the 2019 version of Solidworks?
You're lucky I haven't cleared my old installation off of my PC yet
Take the numbers you have, draw the shape and revolve :-) Without knowing what a0, a1,a2 etc is it's hard to tell you.
Also depends on how you want to approach it, use the dimensions or draw the form and try to get the ratio of surface and volume.
I are no mathematicalizer super genius but my guess is that without knowing what the constants that are known are there are a WHOLE bunch of possible solutions. I just PFA'd some numbers and got pretty close....no I didn't draw it in microns :-)
Matt Juric wrote: Take the numbers you have, draw the shape and revolve :-) Without knowing what a0, a1,a2 etc is it's hard to tell you.
Matt Juric wrote:
a0, a1, and a2 are all just constants - they don't hold units. How did you draw the shape?
Tyler Williams wrote: Matt Juric wrote: Take the numbers you have, draw the shape and revolve :-) Without knowing what a0, a1,a2 etc is it's hard to tell you. a0, a1, and a2 are all just constants - they don't hold units. How did you draw the shape?
Tyler Williams wrote:
I drew a sketch that looked like below and revolved it. the only "Known" number I pulled from what was given was the OD of the cell. I threw in a diameter of the "ring" and adjusted the .8 thickness until I got the right ratio of surface to volume. Without knowing what the a0 et el are referring too I had no idea what the actual dimensions should be. D0 is the OD of the cell. No idea what A0, A2 are and maybe a1 is what I'm showing as 2.6
a0, a1 and a2 are given in the OP Matt;
The shape is symmetrical all around the z axis, as the coefficient on x e y are the same.
What you could do is to draw a 2D funcion sketch on the positive portion of x-z plane (considering y=0 in the formula)
mirror the sketch line with respect to the x axis and then revolve around z axis.
I don't know about Alex Burnett 's solution because I can't open the file.
That's actually exactly what I did. There's an equation driven curve with the following parameters.
x1=0 to x2=3.91
y(x) = 7.82*(sqrt(1-(4*(x^2))/7.82^2))*(.0518+(2.0026*(x^2))/7.82^2+(-4.491*(x^2))/7.82^4)
I then revolved this around the y axis and then mirrored it for the other half.
Alex, did you do calculation for limit, x1 & x2?
The link that Tyler provided listed this equation as one of the roots of y:
If y=0 then x=3.91
I wanted the other limit to begin at 0, although I imagine -3.91 would have worked too to give the full cross section.
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