I want to calculate torque and rpm in small gear? I created motion study, I take some results. But, when I add gravity, result does not change. I think I'm doing something wrong.
Feel free to make any good suggestions.
RPM depends only on the gear ratio. Once you figure the middle gear, then use that one to figure the small gear.
Working out Revolutions Per Minute
Planetary Gear Simulator
1. Why would you think gravity has anything to do with it?
2. Do you know how planetary gears work?
3. What is fixed in your picture?
4. Unless you add some constraints, given what you've shown, the inner gear will rotate at 50rpm.
5. Unless it has any load, at which case it will rotate at zero rpm.
6. You have not specified any input torque. Therefore, you cannot calculate ouptut torque.
7. Except that as you've shown it, the output torque is zero.
1.I thought it might be more difficult to turn a heavier material.
2. yes i did some research
3. The largest gear spins at 50 rpm. I want to calculate the torque of the smallest gear
4.I created a gear mate. what kind of constraint are we talking about?
5. I don't understand exactly what you mean here
6.largest gear mounted on another part and it turns free. I don't know what to define here?
maybe post some screen shots here to show the work condition for your study,......
I added an image for better understanding.
In this arrangement, I'm curious as to what exactly you're going to use to "fix" the axles of the three planets.
Sea lo que sea, if they are fixed then all you have is one big gear, one smaller gear, and one way smaller gear. But in this arrangement the only thing that matters is the ratio of the biggest gear to the smallest gear. The "planet" gears do absolutely nothing with regard to speed change or torque, although they do function to transfer the torque from the rim to the center.
It appears your largest gear is apx 10x the smallest gear. Therefore the output is 500rpm, the output torque is input torque/10.
Please replace 10 with the appropriate actual number.
Also no reason to have 3 of the medium gears in this situation, 1 is sufficient.
David Lane wrote: Also no reason to have 3 of the medium gears in this situation, 1 is sufficient.
David Lane wrote:
I kinda doubt this is the actual arrangement... But if it is, the advantage is structural, and unrelated to torque transmission. The opposing three gears effectively balance out the radial forces of the spur gear train. It minimizes the strength/rigidity required of the central shaft supports.
What you have shown here will not act as a planetary gear set. Planetary gears have a housing that the outer ring is mounted to and is stationary. The input shaft is connected to the sun gear (center ring) the output is connected to the planetary gears (Middle gears).
What you have here is nothing more than a metal disk where the inside is connected to the outside via gears. The torque calculation here will depend entirely on friction, moment, ACCDEC etc and will have nothing to do with gear ratio...well up to the point that the gear ratio is involved in the afore mentioned factors.
If the outer ring is mounted solidly the inner ring would spin free with near zero torque because it's just going to spin the planetary gears around and around and around. The same is true in reverse.
Looks insufficient input parameters to solve the problem.
Thanks for replies. I will search input parameters to solve.
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