I simulate the heating of a steel brick with a side dimensions of 5x5x7mm. I heat one side (3558K). But the opposite side remains completely cold (293.2K). In my opinion, this is unrealistic. What am I doing wrong?
Thank you all.I found a mistake in my modeling.I did not specify the radiation.
The result is much better.
In addition, I replaced the material with a standard one, changed the radiation of the surface, and increased the Computational Domain. The calculation is almost not affected.
Here is the mathematical formula for the thermal conductivity.
Q - heat generation (W).L - distance between the walls (m).
S - cross-sectional area of the brick (m^2).
t1 - temperature on the first wall of the brick (K).
t2 - temperature on the second wall of the brick (K).
Dimensions of my brick 0.2x0.2x0.5m.
In accordance with the formula of thermal conductivity:
Л = (10*0.5)/(0.2*0.2*(299.3-298.15)) = 108.7 W/(m*K)
But for this material the thermal conductivity is 51,9 W/(m*K)
What am I missing? Why theory and modeling do not match?
It suspect that the size of the computational domain is the same size as the brick. So all domain surfaces touching the brick are 293 no matter what.
Energy is going from one place to another. Where is the energy going needs to be included in the model. If going into air then you need to include air in the simulation.
Look your material definition. Heat transfer coefficient may be "a bit unrealistic".
I think you might want to uncheck the heat conduction in solids only if you want the analysis to consider the heat convection to the air and define the ambient temperature.
Also check the material definition, I would recommend using the solidworks pre-defined materials.
you need to have both the thermal conductivity parameter and the specific heat parameter of the material.
Radiation is going off both ends of the brick to the environment.
Place a non-radiating (or very low emissivity) surface on the hot side of the brick.
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