2 Replies Latest reply on Apr 3, 2018 9:30 AM by Nicole Atkinson

    DriveWorks Express

    Nicole Atkinson

      How do I capture a Driven dimension in DriveWorks Express?

      I have a right triangle in the top left corner of the frame I show on the right.  I have a fixed dimension of b=1.3"

      The 2 angles A & B change and other two sides a & c change depending on the input of the sides of larger frame, H1, H2 and W.

      SolidWorks gives me the results of the changes in the large frame but how do I grab those results to use in my formula?

      I need to subtract the Driven dimension a (.7506) from the hypotenuse of the large frame.

      a=(.7506)

      (SQRT(((WindowOpeningHeightH-WindowOpeningShortSideB) ^2)+(WindowOpeningWidthW ^2))-.5) -a

        • Re: DriveWorks Express
          Todd Blacksher

          Nicole,

          I'm not sure, but you might be over-complicating this part.

          If you need "b" to be a fixed length (1.300") and the triangle has a right angle, you should be able to handle everything with relations instead of equations.

          Here is a quick & dirty sketch (fully defined)

          The 1.300" line has a perpendicular relation to the angled line, and it will update accordingly when you change all of the other numbers.

          Not sure if this is what you are after, but this is what it sounded like to me.

          todd

            • Re: DriveWorks Express
              Nicole Atkinson

              Thank you for your reply.  I know that the relationship will update in SolidWorks as the other dimensions change due to their relationships.  I need the resulting dimension of the short leg to deduct it from the overall length of a rail.  I just realized that I can solve for the angle B in the large triangle so now I know one side and one angle to put in the formula.  a= cot(asin (142/163)) x 1.3.

              What I was hoping to do is just grab the dimension of a instead of doing the trigonometry functions.