in the Static Study can anyone tell me what the difference between Applying a force and Applying a pressure? if this question is any where else i apologize i couldn't find any.
Force applies a load to the part. It can be from a point to a large area but if you select 5lbf it will be 5lbf no matter what. Pressure makes the force depend on the area it is applied to, so 5psi applied to a 1in^2 area would be 5lbf distributed load and a 5psi pressure applied to a 10in^2 area would be 50lbf distributed load
Basically, Force can be applied to a point where you need a face to apply pressure
i applied force to a square, and then calculated the PSI to the same square so they would be the "same amount" and im getting different answers
What you did is calculating per square inch, not total pressure on the square
Think about using your hand to push a brick vs a wall - you can apply the same pressure but only brick can be moved
Tom Puttkammer wrote:i applied force to a square, and then calculated the PSI to the same square so they would be the "same amount" and im getting different answers
Tom Puttkammer wrote:
How did you do this calculation?
Do you have a *.sldprt file that you can attach?
This is a simple formula P=F/A If you re-arrange the equation F=PA.
I am doing a demonstration of this tomorrow and need a helper for the demo.
I weigh 165lb.
We will calculate the area of the bottom of my shoe.
I will stand on your chest with one foot while you lay on the floor.
Then I will attempt to balance that same 165lb load on the head of a lag screw with the pointed end of the screw is on your chest.
I think you will then understand the equation P=F/A where F is constant but the A changes (approaches zero).
Actually, the rest of the class will understand the demo - you might have to go to the hospital. (it can be a messy demo)
You will find a lot of detailed information on simulation loads within the SOLIDWORKS Help page... 2018 SOLIDWORKS Help - Structural Loads
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