Assume that an object with a mass of 11.772 kg is placed on a slope with a slope of 10 degrees and the coefficient of friction between the slope and the object is 0.2.
When calculated by hand,
The force that makes the object slip = mgsinθ = 11.772*9.81*sin(10)=20.01N
The friction force = μmgcosθ = 0.2*11.772*9.81*cos(10)=22.73N

In other words, the friction force is higher than the force that makes the